C Program to check whether input alphabet is consonat or not

Here is simple C program to check a input alphabet is consonant or not. a,e,i,o,u,A,E,I,O and U are vowel, except these alphabets, all alphabets are consonant.

#include<stdio.h>
int main()
{
 char ch;
 printf("Enter a alphabet: ");
 scanf("%c",&ch);
 if(ch=='a'||ch=='e'||ch=='i'||ch=='o'||ch=='u')
 {
  printf("Alphabet is not consonant \n");
 }
 else
 if(ch=='A'||ch=='E'||ch=='I'||ch=='O'||ch=='U')
 {
  printf("Alphabet is not consonant \n");
 }
 else
 {
  printf("Alphabet is consonant \n");
 }
 return 0;
}

Another C program using switch loop

#include<stdio.h>
int main()
{
 char ch;
 printf("Enter a alphabet: ");
 scanf("%c",&ch);
 switch(ch)
 {
  case 'a':
  case 'e':
  case 'i':
  case 'o':
  case 'u':
  case 'A':
  case 'E':
  case 'I':
  case 'O':
  case 'U':
  printf("Alphabet is not consonant \n");
  break;
  default:
  printf("Alphabet is consonant \n");  
 }
 return 0;
}